Here we understand the what is buffer, buffer capacity & its equitation, applications of buffers
The buffer equation, also known as the Henderson-Hasselbalch equation, is used to calculate the pH of a buffer solution. It is given by:
Let’s understand ionization of weak acid
The Henderson-Hasselbalch equation is a fundamental equation in chemistry and biochemistry that relates the pH of a solution to the pKa of its acidic component and the ratio of the concentrations of the conjugate base and the weak acid. The equation is given by:
The derivation of the Henderson-Hasselbalch equation involves the following steps:
Start with the equilibrium expression for the dissociation of the weak acid:
HA ⇌ H+ + A-
The equilibrium constant (Ka) for the dissociation of the weak acid is given by:
Ka = [H+][A-]/[HA]
Take the negative logarithm of both sides of the equation to get:
-log(Ka) = -log([H+][A-]/[HA])
Use the Definition of pH- The negative logarithm of the hydrogen ion concentration ([H+]) is equal to the pH of the solution:
pH = -log([H+])
Rearrange the equation to isolate the pH term:
pH = -log([H+]) = -log([H+]) + log([HA]/[A-]) – log(Ka)
Combine the logarithms using the properties of logarithms:
pH = -log([H+]) + log([HA]/[A-]) – log(Ka)
Use the Definition of pKa- The negative logarithm of the acid dissociation constant (Ka) is equal to the pKa of the weak acid:
pKa = -log(Ka)
Substitute pKa for -log(Ka) in the equation:
pH = -log([H+]) + log([HA]/[A-]) – pKa
Rearrange the equation to get the Henderson-Hasselbalch equation:
pH = pKa + log([A-]/[HA])
This equation relates the pH of a solution to the pKa of its acidic component and the ratio of the concentrations of the conjugate base and the weak acid. It is a useful tool for understanding and predicting the behavior of weak acid-base systems.
The Henderson-Hasselbalch equation can also be applied to weak bases.
For a weak base, B, the dissociation reaction is:
B + H2O ⇌ BH+ + OH-
The equilibrium constant (Kb) for the dissociation of the weak base is given by:
Kb = [BH+][OH-]/[B]
Where:
– [BH+] is the concentration of the conjugate acid
– [OH-] is the concentration of hydroxide ions
– [B] is the concentration of the weak base
Taking the negative logarithm of both sides of the equation, we get:
-log(Kb) = -log([BH+][OH-]/[B])
Using the definition of pOH (the negative logarithm of the hydroxide ion concentration), we can rewrite the equation as:
pOH = -log([OH-]) = -log([OH-]) + log([BH+]/[B]) – log(Kb)
Rearranging the equation, we get:
pOH = pKb + log([BH+]/[B])
Since pH + pOH = 14 (at 25°C), we can substitute pOH with 14 – pH:
14 – pH = pKb + log([BH+]/[B])
Rearranging the equation, we get:
pH = 14 – pKb – log([BH+]/[B])
This equation is similar to the Henderson-Hasselbalch equation for weak acids, but with the pKb of the weak base instead of the pKa of the weak acid. It relates the pH of a solution to the pKb of its basic component and the ratio of the concentrations of the conjugate acid and the weak base.
Buffer capacity is a measure of the ability of a buffer solution to resist changes in pH when small amounts of acid or base are added. It is defined as the amount of strong acid or base that must be added to change the pH of a solution by one unit.
Buffer capacity depends on the concentrations of the weak acid and its conjugate base (or the weak base and its conjugate acid), as well as the pH of the solution.
The buffer capacity (β) of a solution is defined as the change in the concentration of either the acid (ΔA) or the base (ΔB) divided by the change in pH (ΔpH) when a small amount of strong acid or base is added to the solution. The formula for buffer capacity is:
β = ΔA or ΔB / ΔpH
Where:
– β is the buffer capacity
– ΔA or ΔB is the change in the concentration of either the acid or the base
– ΔpH is the change in pH
For example, if a buffer solution contains 0.1 M acetic acid (CH3COOH) and 0.1 M sodium acetate (CH3COONa), and the pH of the solution changes from 4.0 to 4.5 when a small amount of strong acid is added, the buffer capacity can be calculated as follows:
ΔA = 0.1 M – 0.05 M = 0.05 M
ΔpH = 4.5 – 4.0 = 0.5
β = ΔA / ΔpH = 0.05 M / 0.5 = 0.1 M/pH
This means that 0.1 mole of strong acid or base must be added to the solution to change the pH by one unit. A higher buffer capacity indicates that the buffer solution can resist changes in pH more effectively.
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